TANCET, CEETA PG answer key 2024 out at tancet.annauniv.edu; marking scheme, percentile calculation

NEW DELHI: Anna University has issued the answer keys for Tamil Nadu Common Entrance Test (TANCET) 2024 and Common Engineering Entrance Test for Admission Postgraduate (CEETA PG) 2024 today, March 13. Candidates who appeared in the TANCET, CEETA PG exam 2024 can download the answer key through the official website, tancet.annauniv.edu.

To download the TANCET, CEETA PG answer key 2024, candidates will have to use their email ID and password as login credentials. As per the official schedule, the TANCET exam was held on March 9 and the CEETA PG exam was conducted on March 10.

The TANCET, CEETA PG answer key 2024 issued by Anna University is a provisional answer key. Candidates who are not satisfied with this answer key will be able to raise objections against it.

The TANCET exam is conducted annually for candidates who want to get admission to Anna University’s Master of Business Administration (MBA) and Master of Computer Application (MCA) degree programmes. CEETA PG exam is conducted for candidates who seek admission to Master of Engineering (ME), Master of Technology (MTech), Master of Architecture (March), and Master of Planning (MPlan) programmes.

Also readCUET PG 2024 admit card for March 16 exam out at pgcuet.samarth.ac.in; schedule

TANCET Answer Key 2024: Marking scheme

The TANCET 2024 exam will have 100 questions carrying one mark each. For every wrong answer, 1/3 marks will be deducted and zero marks awarded for questions that are not attempted. Multiple shading for any questions will be considered as a wrong answer.

Candidates who have written the TANCET, CEETA-PG will be notified with actual marks and percentile scores, at the time of result publication. However, to avoid projecting negative scoring, the final scorecard contains only the percentile score. The percentile score is calculated using the formula:

Percentile Score =(Y/N)* 100.

Where Y is the number of students who scored lesser marks than the candidate in that examination and N is the total number of students who appeared for the examination.