CSIR UGC NET December answer key 2024 objection facility closes today; results soon

NEW DELHI: The National Testing Agency (NTA) will close the answer key objection window for Central Scientific and Industrial Research–University Grants Commission National Eligibility Test (CSIR-UGC NET) 2024 today, March 14. Candidates who appeared for the CSIR UGC NET 2024 exam can raise their objections against the answer key through the official website, csirnet.nta.ac.in.

Candidates can raise objections against the CSIR-UGC NET 2024 answer key using their application number and date of birth. Candidates will have to pay a non-refundable fee of Rs 200 for each objection raised.

The CSIR UGC NET 2024 final answer key will be prepared after evaluating the objections raised by the candidates. Candidates can use CSIR UGC NET 2024 answer key to calculate their probable scores.

The CSIR UGC NET 2024 exam was held on February 28, March 1, and 2 in a computer-based mode across 326 centres in 164 cities.

CSIR UGC NET 2024: How to calculate probable scores?

As per the CSIR UGC NET 2024 marking scheme, candidates can calculate their scores based on the correct responses. The paper included MCQ question based on maths, physical science, life sciences, earth atmospheric, ocean, and planetary sciences subjects.

CSIR UGC NET scores: Calculation formulae

CSIR UGC NET 2024 results

NTA will soon announce the CSIR NET 2024 results through its official website, csirnet.nta.ac.in. Candidates will require their registration number, date of birth and password to download the CSIR NET 2024 results. The results will include qualifying status, as well as the marks secured in the exam.

CSIR NET 2024 cut-offs will be released in online mode for all subjects including category wise cut-off marks. To qualify for the CSIR UGC NET 2024, the candidates must secure subject-wise cut and category-wise cut off qualifying marks.