How will NTA prepare CUET 2022 results? Normalisation, marking scheme explained
CUET result 2022 will be announced by September 15 at cuet.samarth.ac.in. The NTA explains the CUET UG 2022 normalisation process and marking scheme.
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Try NowAnu Parthiban | September 14, 2022 | 09:34 AM IST
NEW DELHI: The National Testing Agency (NTA) held the Common University Entrance Test (CUET 2022) for 14,90,000 candidates in six phases at 489 exam centres. There has been a lot of confusion regarding how the NTA will compare and calculate the CUET 2022 scores for a subject held on different dates. Here’s all you need to know about how the NTA will prepare CUET results 2022.
The Common University Entrance exam for admission to central universities and other participating institutes was conducted in 27 different subjects with freedom to the candidates to choose a combination of these subjects.
In order to ensure that the admission are made based on a score that accurately compares the performance of the students, the NTA informed that the CUET UG 2022 raw score of each candidate in each subject will be normalised using the “Equipercentile method”.
“Unlike CUET-UG, other entrance examinations are limited to fewer subjects. In single session entrance tests, one common statistically established method is to transform the raw marks into a common uniform scale using the percentile method so that the performance of students can be compared to each other,” the testing agency said. The NTA explained the CUET 2022 normalisation process and marking scheme as given below.
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A committee headed by senior professor from Indian Statistical Institution Delhi and comprising of senior professors from Indian Institute of Technology (IIT) Delhi and University of Delhi (DU) had detail deliberations to arrive at methodology.
What is equipercentile method?
In the equipercentile method, percentile for each candidate is calculated using the raw marks of the candidate as compared to the raw marks of others in the same session. This is done for every session across multiple days for the same subject. These percentiles are then equated, and converted into normalised marks. For sessions with smaller number of candidates , these are clubbed with bigger sessions.
Using only percentiles in subjects such as Sports or Fine Arts will not be accurate as some weightage (eg 25%) is given to the skill component by some universities. Therefore, in a particular university, if the raw marks of the skill component has a certain weightage, say 25%, it can be added to the remaining 75% weightage of the normalized marks to prepare the rank list.
Each subject for which examination is held in multiple shifts, raw marks are converted into normalised marks on a common scale.
How is CUET UG results 2022 prepared?
Step 1 - Convert raw scores into CUET percentile scores
To calculate the normalized marks across different sessions in a given subject, the percentile of each group of these students for each shift is calculated using the raw marks they have scored.
Let us say in a given shift, 100 students have appeared for the test. We sort their marks in decreasing order. Let us assume that one student among these 100 students has scored 87% marks. Now let us assume that 80 out 100 students have secured less than or equal to 87% marks. The percentile of this student with 87% marks would be 80/100=0⋅8. The percentile so calculated will always be between 0 and 1 and it is usually rounded off to the requisite number of decimal places.
Step 2 - Arranging CUET percentiles in a descending order
Let us now assume that there are six students (Stu1, Stu2, Stu3, Stu4, Stu5, Stu6). Three of them (Stu2, Stu4, Stu6) have taken the test in shift-1 and the remaining (Stu1, Stu3, Stu5) in shift-2 but all in the same subject. Using the raw marks of these students, first the percentiles (PStu1 , PStu2 , PStu3 , PStu4 , PStu5 , PStu6) of these six students in a given subject are calculated and are sorted in decreasing order. Their Raw Marks (RMStu1 , RMStu2 , RMStu3 , RMStu4 , RMStu5 , RMStu6 ) in the test in each shift are also noted corresponding to their percentiles.
Step 3 - Calculate the marks of the students using linear interpolation
Since some students (Stu2,Stu4,Stu6) have attended shift-1 and not shift-2, their raw marks in shift-2 will not be present. Similarly the students (Stu1,Stu3,Stu5) who wrote the exam in shift-2, will have no marks in shift-1. These missing marks of each candidate in each shift are then calculated using a method called interpolation. Interpolation is a mathematical way of estimating missing marks of the students who are absent in one shift because they have already taken the test in the other shift.
Step 4 - Calculate the normalised marks on common scale
“Each percentile value of the candidates sorted in a descending order will have marks for both shifts, raw marks and interpolated marks. Raw marks are available in the shift where the student has a written test and interpolated marks are estimated in the other shift because the student could not have a written test for a second time in the same subject. For each student, we then calculate the average of the actual raw marks in one shift and the marks obtained using interpolation in the other shift,” the official notice read.
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