CSIR UGC NET 2024 answer key objection window closes today; challenge fee

NEW DELHI: The National Testing Agency (NTA) will close the objection window against the Joint Central Scientific and Industrial Research–University Grants Commission National Eligibility Test (JOINT CSIR-UGC NET) July 2024 provisional answer key along today, August 11. Candidates who appeared for the exam and are not satisfied with the solutions can raise objections against the CSIR UGC NET answer key 2024 through the official website, csirnet.nta.ac.in.

Candidates will have to use their login credentials such as registration number and date of birth along with supporting documents to raise objections against the CSIR UGC NET 2924 provisional answer key.

The CSIR UGC NET 2024 exam was held on July 25, 26, 27 for awarding research fellowships to eligible candidates. examination was administered in computer-based test (CBT) mode in two shifts- first shift from 9 am to 12 noon and second shift from 3 pm to 6 pm. A total of 2,25,335 candidates appeared for the in the CSIR UGC NET exam this year.

CSIR UGC NET 2024 objection fee

Candidates who are not satisfied with the provisional answer key will be able to raise objections by paying a non-refundable challenge fee of Rs 200 per question. The examination authority will review the objections received by the candidates and will issue the CSIR UGC NET 2024 final answer key accordingly. The CSIR UGC NET 2024 result will be announced on the basis of final answer key.

The processing fee can be paid online using a debit card, credit card, or net banking. No challenge will be entertained without receipt of the processing fee. The fee towards the challenge will not be accepted through any other mode.

“If the challenge of any candidate is found correct, the Answer Key will be revised and applied in the response of all the candidates accordingly. Based on the revised Final Answer Key, the result will be prepared and declared,” the official notification read.

Candidates can use the CSIR UGC NET 2024 answer key to calculate their probable scores in the exam.