MHT CET 2024 result by June 12 at cetcell.mahacet.org; percentile calculation
Ayushi Bisht | May 30, 2024 | 11:21 AM IST | 1 min read
MHT CET 2024 Result Date: Candidates will have to use their login credentials such as registration number and date of birth to download the MHT CET result 2024.
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Check NowNEW DELHI: The Maharashtra Common Entrance Test (CET) will announce the MHT CET 2024 result by June 12. Candidates who appeared for the exam will be able to download the MHT CET result 2024 for PCB and PCM by visting the official website, cetcell.mahacet.org.
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Candidates will have to use their login credentials such as registration number and date of birth to download the MHT CET result 2024.
"MHT CET 2024 score card containing percentile Score for the respective Group (PCB and PCM) will be made available to the candidate's in their login on or before 12th June, 2024", official notification read.
The MHT CET final answer key 2024 with the modifications highlighted has been made available by the test cell. The authorities have taken 47 objections into consideration.
MHT CET 2024 important dates
Candidates can check the MHT CET PCB, PCM dates in the table given below-
|
Event |
Dates |
|
MHT CET exam date |
PCB - April 22, 23, 24, 28, 29 and 30 PCM - May 2, 3, 4, 9, 10, 11, 15, 16 and 17 |
|
MHT CET PCM result date MHT CET PCB result date |
By June 12, 2024 |
MHT CET 2024 result normalisation
The officials will update the normalisation process for announcing the candidate ranks to determine the percentile score for MHT CET 2024 result. The MHT CET score will be announced as percentile on a scale from 0 to 100. The MHT CET 2024 top scorer will receive a percentile of 100. Also adjusted to the proper percentiles are the marks acquired between the top and lowest grades. A percentile score of 0 is assigned to candidates with lower scores.
Candidates for the MHT CET have their percentile scores computed to five decimal places. The MHT CET 2024 percentile can be calculated by using the formula given below-
MHT CET Percentile Score = 100 * (Number of candidates in the exam with normalized marks ≤ the candidate) ÷ Total number of candidates in the exam.
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