TANCET 2024 final answer key out; normalisation method, marking scheme

NEW DELHI: Anna University Chennai has issued the Tamil Nadu Common Entrance Test (TANCET 2024) final answer key for MBA, MCA, ME, MTech, MArch and MPlan admission. Candidates who appeared in the exam will be able to download the TANCET final answer key from the official website, tancet.annauniv.edu.

The TANCET exam 2024 and Common Engineering Entrance Test and Admission (CEETA PG) was conducted for 39,301 candidates at 40 examination centers in 15 cities in Tamil Nadu. Candidates will have to enter their registration number and password in the login window to download the TANCET final answer key.

Each paper carried 100 multiple choice questions. Each correct answer will be awarded one mark and ¼ marks will be deducted for every wrong answer. Multiple shading will be considered as the wrong answer and 1/4 mark will be reduced. No marks will be reduced for unanswered questions.

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TANCET 2024: How to calculate marks

The CEETA PG question papers for ME, MTech, MArch, MPlan have two common sections, part 1 - engineering mathematics and part 2 - basic engineering and sciences, and the third part has questions from respective disciplines.

“On evaluation, the average marks may vary from discipline to discipline under part 3. Thus, marks of part III will be computed using the formula: Computed Marks of Part III = (X+r)m. Where X is the adjustment factor, r is the raw mark scored by the candidates and m is the multiplication factor used to level the averages of all subjects,” the university said. The normalisation method gives the relative rank of the candidates in any discipline.

Anna University will notify the candidates’ actual marks and percentile score obtained during the declaration of results. The TANCET score card, however, will only have the percentile score.

The percentile score is calculated using the formula: Percentile Score =(Y/N)* 100, where Y is the number of students who scored a lesser mark than the candidate in that examination and N is the total number of students who appeared for the examination.