UPSSSC Junior Assistant Recruitment 2024: Registration begins for vacancies 2,702 from December 23
Alivia Mukherjee | November 26, 2024 | 09:05 PM IST | 1 min read
The junior assistant recruitment 2024 registration deadline is January 22, 2025.
NEW DELHI: The Uttar Pradesh Subordinate Services Selection Commission (UPSSSC) has announced junior assistant recruitment 2024 for a total of 2,916. Interested and eligible candidates can apply for the UPSSSC junior assistant recruitment 2024 by visiting the official website upsssc.gov.in. The junior assistant recruitment 2024 registrations will begin from December 23.
As per the official notice, the junior assistant recruitment 2024 registration deadline is January 22. Candidates will also get a fee adjustment facility till January 29. Registered candidates will be able to edit the UPSSSC junior assistant recruitment 2024 application form till January 29.
UPSSSC Junior Assistant Recruitment 2024: Eligibility criteria
Candidates can have a look at the eligibility criteria for UPSSSC junior assistant recruitment 2024 below.
- Candidates are required to have passed Class 12 exam from any recognised board.
- Candidates are required to have a minimum speed of 25 words per minute in Hindi and 30 words per minute in English.
- Candidates are required to have a CCC certificate in computer operation awarded by DOEACC Society or any equivalent certificate awarded
- The lower age limit is 18 years old. (As on July 1, 2024)
- The upper age limit is 40 years. (As on July 1, 2024)
Also read UPSC CMS 2024 mark sheet out at upsc.gov.in; 165 candidates selected for category 1
UPSSSC Junior Assistant Recruitment 2024: Exam pattern
The selection process for UPSSSC junior assistant recruitment 2024 includes a written exam. The exam will be conducted in one shift. There will be a total of 100 questions in the UPSSSC junior assistant recruitment 2024 written exam. The duration of the exam is 2 hours. There will be only objective type questions. Candidates will get 1 mark for each correct answer and there will be a negative marking of 0.25 marks for incorrect answer.
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