CUET Result 2022 Declared: 35% miss exam; how percentile score is calculated
Anu Parthiban | September 16, 2022 | 08:48 AM IST | 2 mins read
CUET Percentile Score: The NTA declared the CUET results 2022 based on the equipercentile method. Know how CUET scores are calculated.
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Try NowNEW DELHI: The National Testing Agency (NTA) declared the Common University Entrance Test (CUET) results 2022 today on the official website, cuet.samarth.ac.in. The debut edition of CUET UG 2022 recorded 64.96% attendance.
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A total of 14,90,293 candidates registered for the CUET 2022 exam, making it the second largest entrance exam after the National Eligibility cum Entrance Test (NEET UG 2022) and pushed the Joint Entrance Exam (JEE Main 2022) to third position. As per the CUET result 2022 announced by the NTA, 9,68,201 candidates appeared for the exam. Of the total number of registered candidates, 35 percent missed the exam.
After CUET UG 2022 phase 2 exams were cancelled in many exam centres due to technical, logistics and administrative reasons, the NTA decided to hold exams for these candidates between August 12 to 14. The exam which was scheduled to end on August 20 was held till August 30.
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CUET 2022 phase 1 was held between July 14 to 20 with 2.49 lakh appearing in the exam. 1.91 lakh students appeared each in CUET phase 2 and phase 3. 3.72 lakh candidates appeared in phase 4 , which was held between August 17, 18, 20. 2.01 lakh and 2.86 lakh students appeared in phase 5 and 6 respectively.
How CUET 2022 percentile score is calculated
The NTA declared the CUET results 2022 based on the “Equipercentile method”. In this method, percentile for each candidate is calculated using the raw marks of the candidate as compared to the raw marks of others in the same session. This is done for every session across multiple days for the same subject.
To calculate the normalized marks across different sessions in a given subject, the percentile of each group of these students for each shift is calculated using the raw marks they have scored.
Let us say in a given shift, 100 students have appeared for the test. We sort their marks in decreasing order. Let us assume that one student among these 100 students has scored 87% marks. Now let us assume that 80 out 100 students have secured less than or equal to 87% marks. The percentile of this student with 87% marks would be 80/100=0⋅8. The percentile so calculated will always be between 0 and 1 and it is usually rounded off to the requisite number of decimal places.
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