PUTHAT 2022: Window to raise objections against answer key closes today; Check steps here

PUTHAT 2022 answer key challenge window to close today. Here’s how you can raise objections against PUTHAT answer key 2022.

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Prerna Goel | July 22, 2022 | 09:38 AM IST

NEW DELHI: Panjab University will close the window to challenge the provisional PUTHAT answer key today, July 22. As per the press release, “The candidates can file their objections regarding discrepancy and accuracy of the answers by email at arcet@pu.ac.in, by July 22, 2022, up to 10:00 a.m.” The university will also upload the challenges raised by candidates against PUTHAT 2022 answer key, as well as invite cross-objections regarding the answer keys from July 26, 2022. Candidates will be able to send cross-objections on PUTHAT 2022 answer keys by July 28.

PUTHAT (Panjab University Tourism and Hotel Administration Test) was conducted on July 15 at Chandigarh test centre following which the provisional PUTHAT answer key 2022 was released on July 20. As per the official announcement, the tentative PUTHAT result date is August 05, 2022.
Click here to download PUTHAT 2022 question paper.
Click here to download PUTHAT 2022 answer key.

PUTHAT Answer Key 2022: Important Dates

Events

Dates

PUTHAT 2022 answer key date

July 20, 2022

Last date to challenge PUTHAT answer key

July 22, 2022

PUTHAT 2022 result date

August 05, 2022

How to download the answer key of PUTHAT 2022

Step 1: Visit the official website of PUTHAT 2022 or Panjab University, exams.puchd.ac.in

Step 2: Click on the link provided for the PUTHAT answer key and PUTHAT question paper

Step 3: Download the answer key of PUTHAT and question paper to cross-check your responses and evaluate your scores

How to submit objections against PUTHAT 2022 answer key?

The candidates can file their objections regarding discrepancies and accuracy of the PUTHAT exam answer key by e-mail to arcet@pu.ac.in latest by July 22, 2022.

Calculating total marks in PUTHAT

Use the formula below,

Total marks in PUTHAT 2022 = (Number of correct answers x 1) – (Number of incorrect answers x 0.25)

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