REET 2024 results declared at reet2024.co.in; overall pass percentage stands at 50.77%

REET Result 2024: The pass percentage for the Level 1 exam stands at 62.33%, while Level 2 has recorded a pass percentage of 44.69%.

Check REET 2024 result at reet2024.co.in. (Image: Pexels)
Check REET 2024 result at reet2024.co.in. (Image: Pexels)

Vikas Kumar Pandit | May 8, 2025 | 05:14 PM IST

NEW DELHI: The Rajasthan Board of Secondary Education, Rajasthan (BSER) has announced the results for the Rajasthan Eligibility Examination for Teachers (REET) 2024 for both level 1 and level 2 today. The overall pass percentage for both levels stands at 50.77% in the REET 2024 result.

In the REET 2024 level 1 exam, 62.33% of candidates have passed, while in Level 2, the pass percentage stands at 44.69%. Students who appeared for the exam can check their REET 2024 result through the official website at reet2024.co.in.

The Rajasthan board conducts the REET exam to assess the eligibility of candidates for teaching positions in schools across the state. The REET Level-1 is conducted for candidates seeking to become primary school teachers, specifically for classes 1 to 5. REET Level-2 is conducted for candidates who wish to teach at the upper primary level, which includes classes 6 to 8.

To check the REET 2024 result, students will have to select their level and enter their roll number and date of birth on the official website. Candidates who scored above the minimum qualifying marks declared in the REET exam are considered qualified for teacher positions in Rajasthan schools.

The minimum qualifying marks for candidates for the general category in the REET exam are 60%. For candidates belonging to Scheduled Castes (SC), Scheduled Tribes (ST), Other Backwards Classes (OBC) and Economically Weaker Sections (EWS), the minimum required marks are 55%.

REET Result 2025: Normalisation formula for level 2

The following normalisation formula is used for the REET result 2025 level 2 to adjust scores for variations in exam difficulty across different sessions.

Sij = µ +((Xij - µi)/ σi) * σ

  • µ = Mean of raw score of third shift.
  • σ = Standard deviation of raw scores of the third shift.
  • Xij = Raw marks of the jth candidate in the ith shift.
  • Sij = Scaled Marks of the jth candidate in the ith shift.
  • µi = Mean of raw scores of the ith shift.
  • σi = Standard Deviation of raw scores of the ith shift.

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