JEE Main 2023 Session 2: Tie-breaking method to resolve equal NTA scores

NEW DELHI: The Joint Entrance Examination (JEE Main) 2023 session 2 will be conducted between April 6 and 15 for paper 1 (BE,Btech), paper 2A (BArch) and paper 2B (BPlanning). Candidates appearing for the exam can download city intimation slip and admit cards on the official website – jeemain.nta.nic.in.

After completion of the exam, the National Testing Agency (NTA) will release answer keys and let candidates challenge it within a fixed time period. The JEE Main 2023 result will be based on the final answer key.

Also Read | JEE Main 2023 free mock test links, video lectures at nta.ac.in; session 2 exams from April 6

To determine results, NTA will be using the normalisation process where the raw marks obtained by the candidates will be converted into percentile scores. In case candidates obtain equal NTA scores, the testing agency will use a tie-breaking method to resolve them.

JEE Main 2023: Tie-breaking method for paper 1

Tie between candidates obtaining equal Total NTA scores in Paper 1 (BE, BTech) will be resolved in the following manner in descending order:

• NTA score in mathematics, followed by
• NTA score in physics, followed by
• NTA score in chemistry, followed by
• Candidate with less proportion of a number of attempted incorrect answers and correct answers in all the subjects in the test, followed by
• Candidate with less proportion of a number of attempted incorrect answers and correct answers in mathematics in the test, followed by
• Candidate with less proportion of a number of attempted incorrect answers and correct answers in physics in the test, followed by
• Candidate with less proportion of a number of attempted incorrect answers and correct answers in chemistry in the test followed by
• Older in Age followed by
• Application number in ascending order

Also Read | JEE Main 2023 Session 2 Syllabus: Subject-wise topics for paper 1, 2

JEE Main 2023: Tie-breaking policy for paper 2

Tie between candidates obtaining equal Total NTA scores in Paper 2A (BArch) will be resolved in the following manner:

• NTA score in mathematics, followed by
• NTA score in aptitude test, followed by
• NTA score in drawing test, followed by
• Candidate with less proportion of a number of attempted incorrect answers and correct answers in all the subjects in the Test, followed by
• Candidate with less proportion of a number of attempted incorrect answers and correct answers in mathematics (art-I) in the test, followed by
• Candidate with less proportion of a number of attempted incorrect answers and correct answers in aptitude test (part-II) in the test followed by
• Older in age followed by
• Application number in ascending order

Also Read | No proposal for one-time relaxation in JEE Main 2023 eligibility criteria: Govt

JEE Main 2023: Method of resolving ties in paper 2B

Tie between candidates obtaining equal Total NTA scores in BPlanning will be resolved in the following manner:

• NTA score in mathematics, followed by
• NTA score in aptitude test, followed by
• NTA score in planning based questions, followed by
• Candidate with less proportion of a number of attempted incorrect answers and correct answers in all the subjects in the Test, followed by
• Candidate with less proportion of a number of attempted incorrect answers and correct answers in mathematics (part-I) in the test, followed by
• Candidate with less proportion of a number of attempted incorrect answers and correct answers in aptitude test (part-II) in the test, followed by
• Candidate with less proportion of a number of attempted incorrect answers and correct answers in planning based questions (part-III) in the test followed by
• Older in age followed by
• Application number in ascending order