CEETA PG 2026 answer key out at tancet.annauniv.edu; result on May 23
Sakshi Gupta | May 12, 2026 | 07:56 PM IST | 1 min read
Anna University publishes CEETA PG 2026 provisional answer key; candidates can estimate scores online
Anna University has issued the Common Engineering Entrance Test and Admission - Post Graduate (CEETA PG) 2026 answer key on the official website of Anna University at tancet.annauniv.edu. Applicants can download the answer key by using the details, including email ID and password.
The CEETA PG 2026 answer key contains the officially correct responses to the questions asked in the entrance examination. The exam was conducted on May 10, 2026, while the CEETA PG 2026 results are scheduled to be declared on May 23, 2026.
As per the CEETA PG 2026 marking scheme, candidates will be awarded four marks for every correct answer, while one mark will be deducted for each incorrect response.
Also read BITSAT 2026 city slip out at admissions.bits-pilani.ac.in; BTech exam from May 24
CEETA PG 2026: Important dates
The important dates for the CEETA PG 2026 are as follows:
|
Events |
Dates |
|
CEETA PG exam date |
May 10, 2026 |
|
CEETA PG 2026 answer key date |
May 12, 2026 |
|
Final CEETA PG answer key release date |
May 1, 2026 |
|
Result date |
May 23, 2026 |
How to download the CEETA PG 2026 answer key?
Candidates can download the CEETA PG answer key 2026 by following the steps given below:
- Visit the official website at tancet.annauniv.edu
- Click on the “Answer Key Download” link
- The CEETA PG answer key PDF will appear on the screen
- Download the CEETA PG answer key PDF and take a printout for further reference
Also read 'Years of hard work wasted': NEET aspirants, parents and teacher react to exam cancellation
Candidates can estimate their probable scores by comparing their responses with the official answer key. To calculate the expected score, candidates should multiply the number of correct answers by four and subtract one mark for every incorrect response. The formula used for calculation is: Expected Score = (Number of Correct Responses × 4) − (Number of Incorrect Responses × 1).
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